Unit 4 · Spec 3.3.14

Organic Synthesis

Designing better organic processes (no solvent, safe starting materials, fewer steps, high atom economy), a reaction map of 9620 reactions and worked syntheses of up to four steps for OxfordAQA A-Level Chemistry.

1. Designing Better Processes

Chemists try to make products in ways that are safer, cheaper and produce less waste. The 9620 specification asks you to explain four aims.

Aim Why it helps
No solvent Solvents can be toxic and flammable. They must be removed and disposed of. They add cost and waste.
Non-hazardous starting materials Safer for workers and the environment. The safety measures needed are cheaper.
Fewer steps Each step loses some product. Fewer steps also mean less energy, time and waste.
High atom economy More of the reactant atoms end up in the product, so there is less waste.

Why fewer steps matter

The overall yield is the product of the yields of each step.

Worked Example: Overall Yield
A synthesis has three steps. Each step has a yield of 80%. Calculate the overall yield.

Overall yield = 0.8 × 0.8 × 0.8 = 0.512

Overall yield = 51%. Almost half of the possible product is lost, even though each step looks efficient.

Why atom economy matters

% atom economy = (Mr of the desired product ÷ total Mr of all reactants) × 100

  • Addition reactions have 100% atom economy. All the reactant atoms end up in one product.
  • Substitution and elimination reactions have a lower atom economy. They always make a second product, which is often waste.
Examiner Tip

When you explain one of these aims, link it to cost, safety or waste. For example: "fewer steps means a higher overall yield, so less starting material is wasted".

2. Reaction Map of 9620 Reactions

Use this table to plan a synthesis. Find your starting material in the first column. Then follow the reactions to your target.

From Reagent and conditions To Spec
alkaneCl₂, UV lightchloroalkane3.3.2.4
alkeneHBrbromoalkane3.3.4.2
alkeneconc. H₂SO₄, then wateralcohol3.3.4.2
alkeneBr₂1,2-dibromoalkane3.3.4.2
halogenoalkaneNaOH(aq), warmalcohol3.3.3.1
halogenoalkaneKCN in ethanol/water, refluxnitrile (one more C)3.3.3.1
halogenoalkaneexcess NH₃ in ethanol, heat in a sealed tubeprimary amine3.3.3.1
halogenoalkaneprimary amine (excess halogenoalkane gives more)secondary/tertiary amine, quaternary ammonium salt3.3.11.3
halogenoalkaneKOH in ethanol, refluxalkene3.3.3.2
primary alcoholacidified K₂Cr₂O₇, distilaldehyde3.3.5.1
primary alcoholacidified K₂Cr₂O₇ (excess), refluxcarboxylic acid3.3.5.1
secondary alcoholacidified K₂Cr₂O₇, refluxketone3.3.5.1
alcoholconc. H₂SO₄ or H₃PO₄, heatalkene3.3.5.2
aldehyde or ketoneNaBH₄(aq)alcohol3.3.8.1
aldehyde or ketoneKCN then dilute acidhydroxynitrile3.3.8.1
carboxylic acid + alcoholconc. H₂SO₄, warmester3.3.9.1
esterNaOH(aq) or dilute acid, refluxcarboxylate or acid + alcohol3.3.9.1
acyl chloride or acid anhydridewater / alcohol / NH₃ / primary amineacid / ester / amide / N-substituted amide3.3.9.2
nitrileH₂ with Ni catalyst (or LiAlH₄)primary amine3.3.11.1
benzeneconc. HNO₃ + conc. H₂SO₄, below 55 °Cnitrobenzene3.3.10.2
nitrobenzeneSn + conc. HCl, then NaOHphenylamine3.3.11.1
benzeneRCOCl + AlCl₃phenyl ketone3.3.10.2
benzeneRCl + AlCl₃alkylbenzene3.3.10.2
methylbenzeneCl₂, UV light(chloromethyl)benzene3.3.10.2

How to Plan a Synthesis

  • Compare the start and the target. Which functional group changes? Does the number of carbon atoms change?
  • Adding one carbon atom: use KCN. A halogenoalkane gives a nitrile. An aldehyde or ketone gives a hydroxynitrile.
  • Adding carbons to a benzene ring: use an acyl chloride with AlCl₃ (Friedel-Crafts acylation).
  • Work backwards from the target if you are stuck. Ask: "what could I make this from?"
  • For each step, give the reagent, the conditions and the product.

Beyond the OxfordAQA specification: a nitrile can be hydrolysed to a carboxylic acid by heating with dilute acid. 9620 does not require this reaction.

3. Worked Syntheses

Each step names the reagent, the conditions and the product.

Synthesis A (2 steps, adds a carbon): Bromoethane to Propylamine
Suggest a two-step synthesis of propylamine, CH₃CH₂CH₂NH₂, from bromoethane, CH₃CH₂Br.

Step 1: KCN in ethanol/water, reflux → propanenitrile, CH₃CH₂CN.

CH₃CH₂Br + KCN → CH₃CH₂CN + KBr

Step 2: H₂/Ni (or LiAlH₄) → propylamine, CH₃CH₂CH₂NH₂.

CH₃CH₂CN + 4[H] → CH₃CH₂CH₂NH₂

Key idea: the target has one more carbon than the start, so the first step uses cyanide.

Synthesis B (2 steps): Propene to Propanone
Suggest a two-step synthesis of propanone, CH₃COCH₃, from propene, CH₃CH=CH₂.

Step 1: Conc. H₂SO₄, then water → propan-2-ol, CH₃CH(OH)CH₃. This is the major product, because it forms via the more stable secondary carbocation.

Step 2: Acidified K₂Cr₂O₇, reflux → propanone.

CH₃CH(OH)CH₃ + [O] → CH₃COCH₃ + H₂O

Key idea: a secondary alcohol is oxidised to a ketone. The ketone is not oxidised further.

Synthesis C (3 steps): Benzene to N-Phenylethanamide
Suggest a three-step synthesis of N-phenylethanamide, C₆H₅NHCOCH₃, from benzene.

Step 1: Conc. HNO₃ and conc. H₂SO₄ below 55 °C → nitrobenzene.

C₆H₆ + HNO₃ → C₆H₅NO₂ + H₂O

Step 2: Sn and conc. HCl, then NaOH → phenylamine.

C₆H₅NO₂ + 6[H] → C₆H₅NH₂ + 2H₂O

Step 3: Ethanoyl chloride or ethanoic anhydride → N-phenylethanamide.

C₆H₅NH₂ + CH₃COCl → C₆H₅NHCOCH₃ + HCl

Synthesis D (3 steps): Ethene to Ethyl Ethanoate
Suggest a synthesis of ethyl ethanoate, CH₃COOCH₂CH₃. Ethene is the only organic starting material.

Step 1: Conc. H₂SO₄, then water → ethanol. Make enough for two portions.

CH₂=CH₂ + H₂O → CH₃CH₂OH (overall)

Step 2: Oxidise one portion with excess acidified K₂Cr₂O₇ under reflux → ethanoic acid.

CH₃CH₂OH + 2[O] → CH₃COOH + H₂O

Step 3: Warm the ethanoic acid with the second portion of ethanol and a few drops of conc. H₂SO₄ → ethyl ethanoate.

CH₃COOH + CH₃CH₂OH ⇌ CH₃COOCH₂CH₃ + H₂O

Key idea: the ester needs two pieces, an acid and an alcohol. Both come from the same ethanol.

Go deeper

These UK AQA pages cover the same ideas in more detail. They may include content that is not in 9620.

4. Practice Questions

Question 1 (4 marks)
Suggest a two-step synthesis of propanal from 1-bromopropane. Give the reagents and conditions for each step, and name the intermediate.
Show Answer & Mark Scheme

Answer:

  • Step 1: NaOH(aq), warm (1) → propan-1-ol (1).
  • Step 2: acidified K₂Cr₂O₇ with the alcohol in excess, distilling off the aldehyde as it forms (1) → propanal (1).
Question 2 (4 marks)
Suggest a two-step synthesis of butylamine from 1-bromopropane. Give the reagents and conditions for each step, and name the intermediate.
Show Answer & Mark Scheme

Answer:

  • Step 1: KCN in ethanol/water, reflux (1) → butanenitrile (1).
  • Step 2: H₂/Ni or LiAlH₄ (1) → butylamine (1).
Question 3 (1 mark)
A three-step process has yields of 90%, 70% and 85%. Calculate the overall yield.
Show Answer & Mark Scheme

Answer: 0.90 × 0.70 × 0.85 = 0.5355, so the overall yield is 54% (53.6%) (1).

Question 4 (2 marks)
Give two reasons why chemists try to avoid using solvents.
Show Answer & Mark Scheme

Answer: any two of (1 mark each):

  • solvents can be toxic or flammable;
  • they must be removed, which uses energy;
  • they create waste that must be disposed of;
  • they add cost.