Unit 2 · Spec 3.3.1

Introduction to Organic Chemistry

Six types of formula, homologous series, IUPAC naming, how mechanisms show electron movement, structural isomers, and E-Z isomerism with the CIP priority rules.

1. Six Ways to Write a Formula

Chemists use six types of formula. Each one shows a different amount of detail. Here they are for butan-1-ol.

Empirical formula

The simplest whole-number ratio of atoms of each element in a compound.

Molecular formula

The actual number of atoms of each element in a molecule.

Formula type What it shows Butan-1-ol
Empirical Simplest whole-number ratio of atoms C₄H₁₀O
Molecular Actual number of atoms of each element C₄H₁₀O
General A formula for every member of a homologous series CₙH₂ₙ₊₁OH
Structural The arrangement of atoms, carbon by carbon, with no bonds drawn CH₃CH₂CH₂CH₂OH
Displayed Every atom and every bond See the diagram below
Skeletal Carbon chain as a zig-zag line, functional groups drawn in See the diagram below

Displayed formula

Every bond is drawn as a line.

Displayed formula of butan-1-ol C H H C H H C H H C H H H O H

Skeletal formula

  • Each end of a line and each corner is a carbon atom.
  • Hydrogen atoms on carbon are not shown.
  • Atoms other than C and H (for example O, Cl) are drawn in, with any H atoms bonded to them.
Skeletal formulas: butan-1-ol and 2-methylpropane OH butan-1-ol 2-methylpropane

2. Homologous Series

Homologous series

A family of compounds with the same functional group and the same general formula.

  • Each member differs from the next by CH₂.
  • Members have similar chemical properties, because they have the same functional group.
  • Physical properties change gradually. For example, boiling point rises as the chain gets longer.

Series in Unit 2 and Unit 4

Series Functional group Suffix or prefix Example
AlkanesC-C only-anepropane
AlkenesC=C-enebut-1-ene
HalogenoalkanesC-Xchloro-, bromo-, iodo-2-bromopropane
Alcohols-OH-olpropan-2-ol
Aldehydes-CHO-alpropanal
KetonesC=O-onepropanone
Carboxylic acids-COOH-oic acidethanoic acid
Nitriles-C≡N-nitrilepropanenitrile
Amines-NH₂-amineethylamine
Esters-COO--yl -oatemethyl ethanoate

3. IUPAC Naming Rules

You must name chains and rings with up to six carbon atoms. You must also draw a structure from its name.

  1. Find the longest carbon chain that contains the functional group. Name its stem: meth (1), eth (2), prop (3), but (4), pent (5), hex (6).
  2. Number the chain from the end that gives the functional group the lowest number. Then give the substituents the lowest numbers.
  3. Name the substituents (methyl, ethyl, chloro, bromo) in alphabetical order. Use di- or tri- for repeats. Put commas between numbers, and hyphens between numbers and letters.
  4. Use cyclo- for rings.

Worked examples: structure to name

Structure Name Why
CH₃CH(CH₃)CH₂CH₂CH₃2-methylpentaneLongest chain is 5 carbons. The methyl group is on C2.
C(CH₃)₄2,2-dimethylpropaneLongest chain is 3 carbons. Two methyl groups are on C2.
CH₂=CHCHClCH₃3-chlorobut-1-eneThe C=C gets the lowest number (1). Cl is then on C3.
CH₂BrCH₂Br1,2-dibromoethaneTwo Br atoms, so di-. One on each carbon.
CH₃COCH₂CH₂CH₃pentan-2-one5 carbons. The C=O is on C2.
(CH₃)₂CHCH₂OH2-methylpropan-1-olThe OH carbon is C1. The methyl group is on C2.
CH₃CH=CHCH₂CH₂CH₃hex-2-ene6 carbons. The C=C starts at C2.
C₆H₁₁OH (a six-carbon ring with OH)cyclohexanolA ring, so cyclo-. No number is needed for one OH group.
(CH₃)₂CHCH₂Br1-bromo-2-methylpropane3-carbon chain. Bromo before methyl (alphabetical order).
CH₃CH₂CH₂COOHbutanoic acid4 carbons, including the COOH carbon, which is always C1.
Worked Example: Name to Structure
Draw the structural formulas of 2-methylbutan-2-ol and 3-methylbut-1-ene.

2-methylbutan-2-ol: a 4-carbon chain. The OH and a methyl group are both on C2. Structure: CH₃C(OH)(CH₃)CH₂CH₃.

3-methylbut-1-ene: a 4-carbon chain. The C=C is between C1 and C2. A methyl group is on C3. Structure: CH₂=CHCH(CH₃)CH₃.

4. Mechanisms: How Chemists Show Electron Movement

A covalent bond can break in two ways.

Homolytic fission

Each atom gets one electron from the bond. This makes two radicals. A radical has an unpaired electron, shown as a dot, for example Cl•.

Heterolytic fission

One atom gets both electrons from the bond. This makes two ions, one positive and one negative.

Curly arrow rules

  • A curly arrow shows the movement of a pair of electrons. A double-headed arrow means a pair.
  • An arrow starts at a lone pair or at a covalent bond.
  • It ends at an atom, or between two atoms where a new bond forms.
Curly arrows: OH⁻ attacking bromoethane H O − nucleophile C δ+ CH₃ H H Br δ− CH₃CH₂OH + Br⁻ Arrow 1 starts at a lone pair. Arrow 2 starts at a bond.

Radical mechanisms use no curly arrows

For a free radical mechanism, show each radical with a dot. Write a balanced equation for each step: initiation, propagation and termination. For example, for methane and chlorine:

  • Initiation: Cl₂ → 2Cl•
  • Propagation: Cl• + CH₄ → HCl + •CH₃, then •CH₃ + Cl₂ → CH₃Cl + Cl•
  • Termination: •CH₃ + Cl• → CH₃Cl

See the full mechanism on the Alkanes page.

Nucleophile

An electron-pair donor. It is attracted to a δ+ carbon atom. Examples: OH⁻, CN⁻, NH₃.

Electrophile

An electron-pair acceptor. It is attracted to regions of high electron density. Examples: H⁺, Br₂ when polarised, NO₂⁺.

5. Structural Isomers

Structural isomers

Compounds with the same molecular formula but a different structural formula.

Type What changes Examples
Chain The carbon chain is arranged differently (straight or branched) butane CH₃CH₂CH₂CH₃ and 2-methylpropane CH₃CH(CH₃)CH₃ (both C₄H₁₀)
Position The functional group is in a different position on the same chain propan-1-ol and propan-2-ol (both C₃H₈O); 1-bromobutane and 2-bromobutane (both C₄H₉Br)
Functional group The functional group is different propanal CH₃CH₂CHO and propanone CH₃COCH₃ (both C₃H₆O); ethanol CH₃CH₂OH and methoxymethane CH₃OCH₃ (both C₂H₆O)

6. Stereoisomers and E-Z Isomerism

Stereoisomers

Compounds with the same structural formula but a different arrangement of the atoms in space.

E-Z isomerism is one type of stereoisomerism. It needs two things:

  • Restricted rotation about the C=C double bond.
  • Two different groups on each carbon of the C=C.

Cahn-Ingold-Prelog (CIP) priority rules

  1. Look at each carbon of the C=C on its own. The atom with the higher atomic number has the higher priority.
  2. If the two atoms are the same, compare the atoms joined to them, at the first point of difference. For example, CH₂CH₃ beats CH₃. Both start with C, but ethyl's next set (C, H, H) beats methyl's (H, H, H).

Z (zusammen, together)

The two higher-priority groups are on the same side of the C=C.

E (entgegen, opposite)

The two higher-priority groups are on opposite sides of the C=C.

Worked example 1: but-2-ene

On each carbon, CH₃ beats H.

E and Z but-2-ene C C CH₃ H CH₃ H (Z)-but-2-ene CH₃ groups on the same side C C CH₃ H H CH₃ (E)-but-2-ene CH₃ groups on opposite sides Blue = higher priority group on each carbon

Worked example 2: 2-chlorobut-2-ene, CH₃C(Cl)=CHCH₃

On C2, Cl beats CH₃ (atomic number 17 beats 6). On C3, CH₃ beats H. In the Z isomer, Cl and the C3 methyl group are on the same side.

E and Z 2-chlorobut-2-ene C C Cl H₃C CH₃ H (Z)-2-chlorobut-2-ene Cl and CH₃ on the same side C C Cl H₃C H CH₃ (E)-2-chlorobut-2-ene Cl and CH₃ on opposite sides Blue = higher priority group on each carbon

Worked example 3: 3-methylpent-2-ene, CH₃CH=C(CH₃)CH₂CH₃

On C2, CH₃ beats H. On C3, both groups start with C, so use the second-atom rule: ethyl (C, H, H) beats methyl (H, H, H).

E and Z 3-methylpent-2-ene C C H₃C H CH₂CH₃ CH₃ (Z)-3-methylpent-2-ene CH₃ and CH₂CH₃ on the same side C C H₃C H CH₃ CH₂CH₃ (E)-3-methylpent-2-ene CH₃ and CH₂CH₃ on opposite sides Blue = higher priority group on each carbon
No E-Z isomers

But-1-ene, CH₂=CHCH₂CH₃, has no E-Z isomers. C1 carries two H atoms, so it does not have two different groups.

Go deeper

These UK AQA pages cover the same ideas in more detail. They may include content that is not in 9620.

7. Practice Questions

Question 1 (4 Marks)
Draw and name the four structural isomers of C₄H₉Br.
Show Answer & Mark Scheme
  • 1-bromobutane, CH₃CH₂CH₂CH₂Br (1 mark)
  • 2-bromobutane, CH₃CHBrCH₂CH₃ (1 mark)
  • 1-bromo-2-methylpropane, (CH₃)₂CHCH₂Br (1 mark)
  • 2-bromo-2-methylpropane, (CH₃)₃CBr (1 mark)
Question 2 (2 Marks)
Explain why pent-2-ene has E-Z isomers but pent-1-ene does not.
Show Answer & Mark Scheme
  • There is restricted rotation about the C=C. (1 mark)
  • In pent-2-ene, each carbon of the C=C has two different groups. In pent-1-ene, C1 has two H atoms. (1 mark)
Question 3 (2 Marks)
Name CH₃CH(CH₃)CH₂OH and CH₃COCH₂CH₃.
Show Answer & Mark Scheme
  • CH₃CH(CH₃)CH₂OH is 2-methylpropan-1-ol. (1 mark)
  • CH₃COCH₂CH₃ is butan-2-one. (1 mark)
Question 4 (1 Mark)
Give the empirical formula of hex-1-ene.
Show Answer & Mark Scheme

CH₂ (1 mark). Hex-1-ene is C₆H₁₂, and the simplest ratio is 1 : 2.

Question 5 (2 Marks)
Is (CH₃)₂C=CHCH₃ able to show E-Z isomerism? Explain.
Show Answer & Mark Scheme
  • No. (1 mark)
  • One carbon of the C=C has two identical CH₃ groups. (1 mark)