Unit 1 · Spec 3.2.3

Group 7: The Halogens

Electronegativity and boiling point trends, displacement reactions, halide reducing ability with H₂SO₄, the silver nitrate test, chlorine in water treatment and bleach production.

2. Oxidising Ability and Displacement Reactions

Oxidising Agent

An electron acceptor. Halogen atoms gain electrons to form 1⁻ halide ions: \[ \text{X}_2 + 2e^- \rightarrow 2\text{X}^- \]

Oxidising ability decreases down Group 7: F₂>Cl₂>Br₂>I₂. As atomic radius and electron shielding increase, incoming electrons experience weaker electrostatic attraction to the halogen nucleus.

Displacement Reactions

A more reactive halogen will displace a less reactive halide ion from aqueous solution:

  • \(\text{Cl}_2(aq) + 2\text{Br}^-(aq) \rightarrow 2\text{Cl}^-(aq) + \text{Br}_2(aq)\) (Solution turns yellow-orange).
  • \(\text{Cl}_2(aq) + 2\text{I}^-(aq) \rightarrow 2\text{Cl}^-(aq) + \text{I}_2(aq)\) (Solution turns brown).
  • \(\text{Br}_2(aq) + 2\text{I}^-(aq) \rightarrow 2\text{Br}^-(aq) + \text{I}_2(aq)\) (Solution turns brown).

No reaction happens when a halogen is added to its own halide or to a halide above it in the group, for example Br₂ + Cl⁻ or I₂ + Br⁻.

3. Reducing Ability of Halide Ions with Concentrated Sulfuric Acid

Reducing ability increases down Group 7: \(\text{F}^- < \text{Cl}^- < \text{Br}^- < \text{I}^-\). Iodide ions have the largest ionic radius and greatest shielding, so their outer electrons are most easily lost.

Solid Halide Reaction Type Observations Products Formed
NaCl Acid-base only (no redox) Steamy fumes turning moist blue litmus paper red. \(\text{HCl}(g) + \text{NaHSO}_4(s)\)
NaBr Acid-base AND Redox Steamy fumes (HBr), orange-brown fumes (Br₂), choking colourless gas (SO₂). HBr,Br₂,SO₂ (Sulfur reduced from +6 to +4)
NaI Strong Redox Steamy fumes (HI), black solid / purple vapour (I₂), choking gas (SO₂), yellow solid sulfur (S), rotten egg smell gas (H₂S). HI,I₂,SO₂,S,H₂S (Sulfur reduced from +6 down to -2)

Equations

Sodium chloride (no redox; misty fumes of HCl):

  • NaCl + H₂SO₄ → NaHSO₄ + HCl

Sodium bromide (misty fumes of HBr, then orange-brown fumes of Br₂):

  • NaBr + H₂SO₄ → NaHSO₄ + HBr
  • 2HBr + H₂SO₄ → Br₂ + SO₂ + 2H₂O. Sulfur goes from +6 to +4.

Sodium iodide (purple fumes, a black solid, a yellow solid and a rotten-egg smell):

  • NaI + H₂SO₄ → NaHSO₄ + HI
  • 2HI + H₂SO₄ → I₂ + SO₂ + 2H₂O. Sulfur goes from +6 to +4.
  • 6HI + H₂SO₄ → 3I₂ + S + 4H₂O. Sulfur goes from +6 to 0 (yellow solid).
  • 8HI + H₂SO₄ → 4I₂ + H₂S + 4H₂O. Sulfur goes from +6 to -2 (H₂S smells of rotten eggs).

Why does reducing ability increase down the group?

Down the group, the halide ion is larger, and its outer electrons are further from the nucleus and more shielded. So an electron is lost more easily. I⁻ is the strongest reducing agent: it reduces sulfur all the way to -2. For oxidation states and half-equations, see Redox Equations.

4. Qualitative Testing with Acidified Silver Nitrate

To identify unknown halide ions in solution:

  1. Add dilute nitric acid (HNO₃) to eliminate carbonate (CO₃²⁻) or hydroxide (OH⁻) ions that would produce false precipitates. Never use hydrochloric acid, as it introduces chloride ions!
  2. Add aqueous silver nitrate (AgNO₃): \[ \text{Ag}^+(aq) + \text{X}^-(aq) \rightarrow \text{AgX}(s) \]
  3. Confirm the precipitate by adding dilute and concentrated aqueous ammonia.
Silver nitrate test for halide ions Add dilute HNO₃, then AgNO₃(aq) HNO₃ first removes CO₃²⁻ and OH⁻, which would also give precipitates Cl⁻ (chloride) white precipitate: AgCl dissolves in dilute NH₃ Br⁻ (bromide) cream precipitate: AgBr dissolves in conc. NH₃ only I⁻ (iodide) yellow precipitate: AgI insoluble in conc. NH₃ Ag⁺(aq) + X⁻(aq) → AgX(s) the ammonia test confirms the colour, which can be hard to judge

Explain why

  • Why AgNO₃? The silver halides form precipitates of different colours: AgCl white, AgBr cream, AgI yellow.
  • Why acidify with HNO₃? It removes carbonate and hydroxide ions, which would also form precipitates with Ag⁺. Do not use HCl, because it adds Cl⁻ ions.
  • Why add ammonia? The precipitate colours are hard to tell apart. Their different solubilities in ammonia confirm the halide: AgCl dissolves in dilute NH₃, AgBr dissolves in concentrated NH₃, and AgI does not dissolve in concentrated NH₃.

This test is part of RP3: Qualitative Inorganic Analysis.

5. Disproportionation Reactions of Chlorine

Disproportionation

A redox reaction in which the same element is simultaneously oxidised and reduced.

Household Bleach Production

Chlorine reacts with cold dilute aqueous sodium hydroxide:

\[ \text{Cl}_2(g) + 2\text{NaOH}(aq) \rightarrow \text{NaCl}(aq) + \text{NaClO}(aq) + \text{H}_2\text{O}(l) \]

Chlorine is simultaneously reduced to -1 in NaCl and oxidised to +1 in sodium chlorate(I), NaClO (active ingredient in bleach).

The solution of sodium chlorate(I) is bleach. It is used to disinfect (kill bacteria) and to bleach.

Water Purification

Chlorine disinfects drinking water by killing bacteria:

\[ \text{Cl}_2(aq) + \text{H}_2\text{O}(l) \rightleftharpoons \text{HCl}(aq) + \text{HClO}(aq) \]

The products contain chloride ions and chlorate(I) ions. This is also disproportionation: chlorine goes from 0 to -1 in HCl and to +1 in HClO.

Chloric(I) acid (HClO) acts as a powerful oxidising disinfectant. In sunlight, chlorine reacts with water to form chloride ions and oxygen:

\[ 2\text{Cl}_2(aq) + 2\text{H}_2\text{O}(l) \rightarrow 4\text{HCl}(aq) + \text{O}_2(g) \]

Chlorine in water treatment: benefits and risks

  • Benefit: chlorine kills bacteria in drinking water and prevents diseases spread by water.
  • Risks: chlorine is toxic. It can also react with organic matter in the water to form chlorinated organic compounds.
  • Decision: society decides that the health benefits outweigh the risks, so small, controlled amounts are added.

Go deeper

These UK AQA pages cover the same ideas in more detail. They may include content that is not in 9620.

6. Practice Questions

Practice Problem (4 Marks)
An unlabelled bottle contains a colourless solution known to be sodium bromide. Describe how you would confirm the presence of bromide ions using silver nitrate and ammonia solution.
Show Answer & Mark Scheme

Procedure & Observations:

  • Add dilute nitric acid (HNO₃), followed by aqueous silver nitrate (AgNO₃). (1 mark)
  • A cream precipitate of silver bromide (AgBr) forms. (1 mark)
  • Add dilute ammonia solution: the precipitate does not dissolve. (1 mark)
  • Add concentrated ammonia solution: the precipitate dissolves to produce a colourless solution. (1 mark)
Practice Problem 2 (4 Marks)
Concentrated sulfuric acid is added to solid sodium iodide. One product is hydrogen sulfide. Write an equation for the reaction of HI with H₂SO₄ to form H₂S, give the change in oxidation state of sulfur, and give two observations.
Show Answer & Mark Scheme

Mark Scheme:

  • 8HI + H₂SO₄ → 4I₂ + H₂S + 4H₂O. (1 mark)
  • Sulfur goes from +6 to -2. (1 mark)
  • Any two from: purple fumes; black solid (I₂); yellow solid (S); smell of rotten eggs (H₂S); misty fumes (HI). (2 marks)
Practice Problem 3 (3 Marks)
In the test for halide ions, explain why the solution is first acidified with dilute nitric acid, why hydrochloric acid is not used, and why ammonia solution is added after silver nitrate.
Show Answer & Mark Scheme

Mark Scheme:

  • Nitric acid removes carbonate and hydroxide ions, which would also form precipitates with Ag⁺. (1 mark)
  • Hydrochloric acid would add Cl⁻ ions, giving a white precipitate whatever the halide. (1 mark)
  • The precipitate colours are hard to tell apart, so the different solubilities in ammonia confirm the halide. (1 mark)
Practice Problem 4 (4 Marks)
Chlorine is added to drinking water. Write an equation for the reversible reaction of chlorine with water. Give one benefit and one risk of adding chlorine, and explain why it is still used.
Show Answer & Mark Scheme

Mark Scheme:

  • Cl₂ + H₂O ⇌ HCl + HClO. (1 mark)
  • Benefit: kills bacteria and prevents disease. (1 mark)
  • Risk: chlorine is toxic, or it forms chlorinated organic compounds. (1 mark)
  • The health benefits outweigh the risks. (1 mark)