AQA A-Level› Physical Chemistry› 3.1.6 Chemical Equilibria & Kc› Le Chatelier's Principle

3.1.6Chemical Equilibria and Kc · Lesson 2 of 3

Le Chatelier's Principle

Predict and explain how changes in temperature, pressure, and concentration affect the position of chemical equilibrium.

Le Chatelier's Principle is a powerful qualitative tool used by chemists to predict how a system at equilibrium responds to external changes. By understanding these shifts, industrial chemists can optimise reaction conditions to maximise the yield of valuable products.

Key Principle

When a system in dynamic equilibrium is subjected to an external change, the system shifts its position of equilibrium in a direction that tends to oppose the change.

Le Chatelier's Principle

If a factor (such as temperature, pressure, or concentration) is changed in a system at dynamic equilibrium, the position of equilibrium shifts to counteract the change.

Homogeneous Equilibrium

A reversible reaction in which all the reactants and products are in the same physical state or phase (for example, all are gases or all are dissolved in aqueous solution).

Factors Affecting the Position of Equilibrium

We can manipulate three main external factors to shift the position of a homogeneous equilibrium: concentration, pressure, and temperature. A catalyst, however, behaves differently.

1. Effect of Concentration

If you increase the concentration of a reactant, the system responds by trying to decrease it. It does this by shifting the equilibrium to the right (towards products) to consume the added reactant.

Worked Example 1: Shift in Concentration
In the aqueous equilibrium: \[ \text{Fe}^{3+}\text{(aq, yellow)} + \text{SCN}^-\text{(aq, colourless)} \rightleftharpoons [\text{Fe(SCN)}]^{2+}\text{(aq, deep red)} \] Predict and explain the colour change observed when a few drops of concentrated sodium thiocyanate (NaSCN) are added.

Step 1: Identify the change. Adding NaSCN increases the concentration of thiocyanate ions (SCN⁻) on the reactant side.

Step 2: Apply Le Chatelier's Principle. The system will oppose the increase by consuming SCN⁻ ions.

Step 3: Deduce the shift and final observation. The position of equilibrium shifts to the right (forward direction) to consume the added reactants. Consequently, the concentration of the deep red complex [Fe(SCN)]²⁺ increases, and the solution turns a deeper red colour.

2. Effect of Pressure

Pressure only affects equilibria that involve gases and where there is a difference in the number of moles of gas between the reactant and product sides of the balanced equation.

AQA Examiner Tip

If a reaction has the same number of gaseous moles on both sides, such as H₂(g) + I₂(g) ⇌ 2HI(g), changing the pressure has no effect on the position of equilibrium. Make sure to count the gas stoichiometric coefficients carefully before writing your exam answer.

3. Effect of Temperature

To predict the effect of temperature, you must know whether the forward reaction is exothermic (releases heat) or endothermic (absorbs heat):

Le Chatelier's principle summary 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) ΔH = −197 kJ mol⁻¹ChangeShiftWhyOO+Add more O₂increase concentrationshifts rightremoves some of the added O₂;more SO₃ formsIncrease temperatureforward reaction is exothermicshifts leftendothermic direction absorbsthe heat; less SO₃Increase pressure3 gas moles → 2 gas molesshifts rightto the side with fewer gasmoles; more SO₃Add a catalystlowers activation energyno shiftboth rates increase equally;equilibrium reached faster

4. Effect of a Catalyst

Adding a catalyst has no effect on the position of equilibrium. A catalyst speeds up the rates of the forward and reverse reactions by the exact same factor, by providing an alternative pathway with a lower activation energy. Therefore, the concentrations remain unchanged, but the system reaches its equilibrium state much faster.

Worked Example 2: Explaining Temperature and Pressure Effects
Consider the reversible gaseous reaction: \[ 2\text{SO}_2\text{(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\text{SO}_3\text{(g)} \quad \Delta H = -197\text{ kJ mol}^{-1} \] State and explain the effect on the yield of SO₃ when:
  1. The temperature is increased.
  2. The overall pressure is increased.

Part a: Temperature Increase

The forward reaction is exothermic (ΔH is negative). Increasing the temperature causes the position of equilibrium to shift to the left (the endothermic direction) to absorb the added heat energy. Therefore, the yield of SO₃ decreases.

Part b: Pressure Increase

There are 3 moles of gas on the reactant side (2SO₂ + 1O₂) and 2 moles of gas on the product side (2SO₃). Increasing the pressure causes the position of equilibrium to shift to the right (the side with fewer moles of gas) to lower the pressure. Therefore, the yield of SO₃ increases.

Industrial Compromises: Haber and Contact Processes

In industry, chemical plants must balance the thermodynamic yield of a product against the kinetic rate of the reaction and the financial/safety costs of the equipment.

The Haber Process

Ammonia is produced via the Haber process reaction:

\[ \text{N}_2\text{(g)} + 3\text{H}_2\text{(g)} \rightleftharpoons 2\text{NH}_3\text{(g)} \quad \Delta H = -92\text{ kJ mol}^{-1} \]

According to Le Chatelier's Principle:

AQA Examiner Tip

When discussing compromise conditions, you must mention both the thermodynamic effect (equilibrium yield) and the kinetic effect (rate of reaction). For example: "A lower temperature increases the yield of ammonia because the forward reaction is exothermic, but decreases the rate. Therefore, 450 °C is a compromise temperature that provides a sufficient rate while maintaining a viable yield."

AQA GCSE & IB Chemistry

Study this topic on the go

Get active recall flashcards, notes, and topic quizzes in ChemEasy, or build your revision schedule with ChemPlan IB.

See our apps
← Dynamic Equilibrium Equilibrium Constant Kc →