Structured Questions
Complete each question on paper, then check your answers against the mark scheme.
Question 1: Nucleophilic Addition Mechanism
5 marksWrite the mechanism for the reaction of ethanal with potassium cyanide, KCN, followed by dilute acid, to form 2-hydroxypropanenitrile. Include all necessary curly arrows, lone pairs, and formal charges. [5]
Show Mark Scheme
- Show dipole on C=O bond of ethanal (C delta+, O delta-). [1]
- Curly arrow from the lone pair on the carbon atom of the cyanide ion (:CN-) to the carbonyl carbon atom. [1]
- Curly arrow from the C=O double bond to the oxygen atom. [1]
- Correct structure of the intermediate: CH3-C(CN)(O-)-H (tetrahedral carbon, negative charge on oxygen). [1]
- Curly arrow from the lone pair on the negative oxygen atom to a proton (H+ from the acid) to form the hydroxyl group. [1]
Question 2: Reduction of Carbonyl Compounds
4 marksA chemist reduces butanone using sodium tetrahydridoborate(III), NaBH₄.
(a) Write a balanced chemical equation for this reduction. Use [H] to represent the reducing agent. [1]
(b) Identify the nucleophile in this reaction and draw the first step of the mechanism, showing how it attacks the butanone molecule. [3]
Show Mark Scheme
(a)
- CH₃COCH₂CH₃ + 2[H] → CH₃CH(OH)CH₂CH₃ [1]
(b)
- Nucleophile: Hydride ion / H⁻ (with lone pair: :H⁻) [1]
- Mechanism first step:
- Show dipole on carbonyl group (C delta+, O delta-). [1]
- Curly arrow starting from the lone pair on the H⁻ ion to the carbonyl carbon, and a second curly arrow from the C=O double bond to the oxygen atom. [1]
Question 3: Distinction of Carbonyls
4 marksDescribe how the student could use Fehling's solution to distinguish between samples of propanal and propanone. Write a half-equation showing the reduction of copper(II) ions in the reagent. [4]
Show Mark Scheme
- Add Fehling's solution to both samples and heat/warm in a water bath. [1]
- Observation with Propanal (aldehyde): Blue solution forms a red / brick-red precipitate of copper(I) oxide (Cu₂O). [1]
- Observation with Propanone (ketone): Solution remains blue / no reaction. [1]
- Half-equation: 2Cu²⁺ + 2OH⁻ + 2e⁻ → Cu₂O + H₂O (or simply: 2Cu²⁺ + H₂O + 2e⁻ → Cu₂O + 2H⁺) [1]
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