Worked Example: Lewis Formula for CO₂
Problem: Draw the Lewis structure for carbon dioxide.
1. Count valence e⁻: C = 4, O = 6 × 2 = 12. Total = 16 e⁻.
2. Skeleton: O – C – O (C is least electronegative → central).
3. Fill outer atoms: Each O needs 8 e⁻. Using single bonds only: 2 (bonds) + 12 (lone pairs) = 14. That leaves 2 spare — but C only has 4 e⁻ around it.
4. Form double bonds: Share two lone pairs from each O → O=C=O. Now C has 8 e⁻ and each O has 8 e⁻.
Answer: O=C=O — two double bonds, two lone pairs on each oxygen.
Think About It
Why does carbon almost always form 4 bonds, never 3 or 5?
Carbon has 4 valence electrons and needs 4 more to complete its octet. It cannot expand its octet because it has no accessible d-orbitals (Period 2 element). This makes it uniquely versatile — it can form 4 single bonds, 2 doubles, 1 double + 2 singles, or 1 triple + 1 single.