IB Chemistry 1.4 1.4.5
1.4.5

Molar Concentration (Solutions)

Concentration

\( c = \frac{n}{V} \)

c = concentration (mol dm⁻³)
n = moles (mol)
V = volume (dm³)

Unit Warning

Volume MUST be in dm³ (not cm³). To convert: divide cm³ by 1000.

Standard Solutions & Dilutions

Standard Solution: A solution of accurately known concentration.

Dilutions: When you add water, moles stay the same but volume increases. Use:

\( c_1V_1 = c_2V_2 \)

Titration Calculation

Problem: 25.0 cm³ of 0.100 mol dm⁻³ NaOH is neutralized by 20.0 cm³ of HCl. Calculate the concentration of HCl.

\( NaOH + HCl \rightarrow NaCl + H_2O \) (1:1 ratio)


1. Moles of NaOH: \( n = c \times V = 0.100 \times 0.0250 = 0.00250 \text{ mol} \)

2. Moles of HCl: (1:1 ratio) = 0.00250 mol

3. Concentration of HCl:

\( c = \frac{0.00250}{0.0200} = 0.125 \text{ mol dm}^{-3} \)

← 1.4.4 Formulas1.4.6 Gases →