IB Chemistry R3.1 R3.1.1
R3.1.1

Bronsted-Lowry Theory

Key Definitions

  • Brønsted-Lowry acid. A proton (H⁺) donor
  • Brønsted-Lowry base. A proton (H⁺) acceptor
  • Conjugate acid-base pair. Two species that differ by exactly one proton
  • Amphiprotic. A substance that can both donate and accept a proton (e.g. H₂O, HCO₃⁻)
  • Amphoteric. A broader term for any species that can react as both acid and base (includes amphiprotic species plus others like Al₂O₃)

Proton Transfer

According to Brønsted-Lowry theory (1923), acid-base reactions involve the transfer of a proton (H⁺) from an acid to a base. In aqueous solutions, free protons do not exist independently. They coordinate with water to form the hydronium ion (H₃O⁺). The notations H⁺(aq) and H₃O⁺(aq) are used interchangeably.

Example 1. Strong acid in water:

HCl(g) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)

HCl donates a proton (acid); H₂O accepts it (base).

Example 2. Weak base in water:

NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

NH₃ accepts a proton (base); H₂O donates one (acid). Note the reversible arrow. NH₃ is a weak base.

Proton Transfer: HCl + H₂O

Diagram: Proton Transfer: HCl + H₂O HCl Acid (donor) + H₂O Base (acceptor) H⁺ Cl⁻ Conj. Base + H₃O⁺ Conj. Acid Conjugate pair 1 Conjugate pair 2

Identifying Conjugate Pairs

A conjugate acid-base pair is two species that differ by exactly one proton. In any acid-base reaction, there are always two conjugate pairs on opposite sides of the equation.

Step-by-Step Method

  1. Identify which reactant loses H⁺ (that's the acid) and which gains H⁺ (that's the base).
  2. Find the conjugate base: remove one H⁺ from the acid and decrease its charge by 1. E.g. H₂SO₄ → HSO₄⁻
  3. Find the conjugate acid: add one H⁺ to the base and increase its charge by 1. E.g. NH₃ → NH₄⁺
  4. Pair them up: Acid ↔ Conjugate Base, Base ↔ Conjugate Acid.

Amphiprotic vs Amphoteric

These terms are often confused but have an important distinction:

All amphiprotic species are amphoteric, but not all amphoteric species are amphiprotic (e.g. Al₂O₃ is amphoteric but has no H atoms to donate).

Examples of Amphiprotic Species

  • Water (H₂O). Donates H⁺ → OH⁻ or accepts H⁺ → H₃O⁺
  • Hydrogencarbonate (HCO₃⁻). Donates H⁺ → CO₃²⁻ or accepts H⁺ → H₂CO₃
  • Hydrogen sulfate (HSO₄⁻). Donates H⁺ → SO₄²⁻ or accepts H⁺ → H₂SO₄
  • Amino acids. The amino group (−NH₂) accepts H⁺; the carboxyl group (−COOH) donates H⁺ → forms a zwitterion

Neutralisation & Acid Reactions

Neutralisation involves the transfer of a proton from an acid to a base, forming a salt and usually water.

Reaction Type Products Example
Acid + Metal hydroxideSalt + WaterHCl + NaOH → NaCl + H₂O
Acid + Metal oxideSalt + WaterH₂SO₄ + CuO → CuSO₄ + H₂O
Acid + CarbonateSalt + Water + CO₂2HCl + CaCO₃ → CaCl₂ + H₂O + CO₂
Acid + HydrogencarbonateSalt + Water + CO₂HCl + NaHCO₃ → NaCl + H₂O + CO₂
Acid + Reactive metalSalt + H₂ (redox!)Mg + 2HCl → MgCl₂ + H₂

Note: Acid + reactive metal is technically a redox reaction (electron transfer), not a neutralisation. Always include state symbols in your exam answers!

⚠️ Common Exam Mistakes

  • Amphoteric ≠ Amphiprotic: Al₂O₃ is amphoteric but not amphiprotic (no H atoms to donate).
  • Forgetting charge adjustments: The conjugate base of H₂PO₄⁻ is HPO₄²⁻, not HPO₄⁻.
  • Misidentifying the base: In NaOH, only the OH⁻ ion is the Brønsted-Lowry base, not the whole molecule.
  • "Neutralisation = pH 7": Not always! The final pH depends on the strengths of the parent acid and base.
  • State symbols: IB mark schemes are strict. Always include (s), (l), (aq), (g).
Study this topic on the go

Get flashcards and quizzes in ChemEasy, or plan your revision with ChemPlan IB.

See our apps →
← Back to R3.1R3.1.2 Strong & Weak →