IB Chemistry R2.1 R2.1.2
R2.1.2

Limiting & Excess Reagents

When reagents are not mixed in exact stoichiometric proportions, one will be used up first — this is the limiting reagent. The other reagent is in excess.

Key Concept

The limiting reagent determines the maximum amount of product that can be formed. Once it is consumed, the reaction stops — regardless of how much excess reagent remains.

How to Identify the Limiting Reagent

Limiting Reagent Method

Step 1 Calculate moles of each Step 2 Divide by coefficient Step 3 Smallest = limiting Example: 5.0 g Fe + 5.0 g S → FeS n(Fe) = 5.0/55.85 = 0.0895 mol   n(S) = 5.0/32.07 = 0.156 mol Ratio is 1:1, so divide by 1: Fe = 0.0895, S = 0.156 Fe = 0.0895 (smallest) → Fe is limiting

Think About It

In the example above, how much excess sulphur (in grams) remains after the reaction?

Moles S used = 0.0895 mol (same as Fe, 1:1 ratio). Moles S remaining = 0.156 − 0.0895 = 0.067 mol. Mass remaining = 0.067 × 32.07 = 2.1 g.

← R2.1.1 StoichiometryR2.1.3 Yield →