AQA A-Level Required Practicals RP3: Rate & Temperature
RP3

RP3: Rate & Temperature

Investigating how the rate of a chemical reaction changes with temperature.

This practical guide outlines the investigation of the effect of temperature on the rate of reaction between sodium thiosulfate and hydrochloric acid. The rate is monitored by measuring the time taken for a fixed amount of sulfur precipitate to form, rendering a marked black cross invisible.

🔑 Core Specification Link

This practical connects directly to topic 3.1.5 Kinetics, exploring collision theory, activation energy (\(E_a\)), and Maxwell-Boltzmann distributions.

Aim

To investigate the effect of temperature on the rate of reaction between sodium thiosulfate and hydrochloric acid, and to show that the reaction rate increases exponentially with temperature.

Equipment List

Experimental Method

  1. Measure 40 cm³ of 0.10 mol dm⁻¹ sodium thiosulfate solution using a measuring cylinder and pour it into a clean 250 cm³ conical flask.
  2. Place the conical flask directly on top of the white card marked with a black cross.
  3. Record the initial temperature of the sodium thiosulfate solution.
  4. Using a smaller measuring cylinder, measure 5 cm³ of 1.0 mol dm⁻¹ hydrochloric acid.
  5. Add the acid to the conical flask, start the stopwatch immediately, and swirl the flask once to mix.
  6. Observe the black cross by looking vertically downwards through the mouth of the flask.
  7. Stop the stopwatch at the exact moment the cross becomes completely obscured by the cloudy yellow-white sulfur precipitate. Record the time in seconds.
  8. Dispose of the toxic reaction mixture immediately in a sodium carbonate stop bath to neutralise dissolved sulfur dioxide gas. Wash the flask thoroughly.
  9. Repeat the experiment at four higher temperatures (approximately 30 °C, 40 °C, 50 °C, and 60 °C). Gently heat the sodium thiosulfate solution in a water bath prior to adding acid, measuring the temperature immediately before acid addition.
  10. Calculate the initial rate for each temperature, which is proportional to \(1 / t\) (where \(t\) is the time taken in seconds).
Disappearing Cross Setup Line of sight (looking down) Cloudy sulfur suspension Black cross on card

Chemical Equation

\[ \text{Na}_2\text{S}_2\text{O}_3(\text{aq}) + 2\text{HCl}(\text{aq}) \rightarrow 2\text{NaCl}(\text{aq}) + \text{S}(\text{s}) + \text{SO}_2(\text{g}) + \text{H}_2\text{O}(\text{l}) \]

The turbidity is caused by the slow precipitation of colloidal solid sulfur, \(\text{S}(\text{s})\).

Safety & Risk Assessment

Hazard Risk Precaution
Sulfur dioxide (\(\text{SO}_2\)) gas Toxic gas that causes respiratory irritation, especially in asthmatics. Carry out the reaction in a well-ventilated laboratory. Place the flask in a neutralising stop bath (sodium carbonate) immediately after recording the time.
Dilute hydrochloric acid Skin and eye irritation. Wear safety goggles and a lab coat. Wash any splashes from skin immediately.
Hot water baths Thermal burns. Handle hot conical flasks with care using tongs or heat-resistant gloves.

Results & Data Analysis

Since the reaction is stopped when a fixed amount of sulfur precipitate has formed, the concentration of sulfur is constant at the endpoint. We can assume that the average rate of reaction is proportional to \(1 / \text{time}\).

Rate vs Temperature Graph Rate (1/t) / s⁻¹ Temperature / °C Exponential rate increase

📈 Theory: Why rate increases with temperature

According to collision theory, a reaction only occurs when reactant particles collide with sufficient energy (greater than or equal to the activation energy, \(E_a\)) in the correct orientation. Increasing the temperature increases the kinetic energy of the particles. Consequently:

  1. A much larger fraction of particles possess energy exceeding the activation energy.
  2. Particles move faster, increasing collision frequency.

The first factor is primary: the Maxwell-Boltzmann distribution shifts to the right, significantly increasing the area under the curve beyond the activation energy barrier. As a result, the frequency of successful collisions increases exponentially.

Sources of Error & Improvements

Error Source Classification Consequence & Mitigation
Subjective endpoint judgement Random Different observers judge when the cross disappears at slightly different times, introducing variability. Mitigation: Use a colorimeter or light sensor connected to a datalogger to record a set level of light transmittance.
Temperature cooling during reaction Systematic Warmed thiosulfate cools down while reacting in the flask, causing a discrepancy between measured temperature and real reaction temperature. Mitigation: Perform the reaction inside a temperature-controlled water bath.
Human reaction time error Random A delay of about 0.2 seconds in starting or stopping the stopwatch. Mitigation: Minimise relative error by using concentrations that yield reaction times between 10 and 100 seconds.

Common Exam Questions

1. Why does the rate of reaction approximately double for every 10 °C rise in temperature, even though the collision frequency only increases by about 2%?

The collision frequency is proportional to the square root of absolute temperature, which changes very little. The key factor is that temperature shifts the Maxwell-Boltzmann distribution, meaning that a much larger fraction of reactant particles have kinetic energies exceeding the activation energy. Thus, a much higher proportion of collisions are successful.

2. Explain why a colorimeter gives more precise results than the disappearing cross method.

The disappearing cross method relies on human eye subjectivity, which varies. A colorimeter measures light transmission electronically and objectively, detecting the exact moment absorbance reaches a set value, which eliminates human reaction time and subjective errors.

3. Why is rate represented by 1/t?

The amount of sulfur precipitate required to hide the cross is identical in every trial. Since the amount of product formed is constant, the average rate of reaction (amount of product / time) is directly proportional to \(1 / t\).

CPAC Skills Assessed

📝 AQA Examiner Tip

When drawing a Maxwell-Boltzmann curve for two temperatures, remember that the peak for the higher temperature (\(T_2\)) must be lower and shifted to the right compared to the peak for the lower temperature (\(T_1\)). The total area under both curves must remain equal, as the total number of particles is constant.

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